const [first, ...rest] = ['a', 'b', 'c', 'd', 'e'];
Array.from(rest, item => console.log(item))

map和foreach都不可以中途停止的，要用都要對(duì)數(shù)組進(jìn)行處理，filter是最好的，for in 也行，for循環(huán)也可以，

var arr = ['a','b','c','d','e'];  
for(let i in arr){
    if(i==0){
        continue;
    }
    console.log(arr[i]);
}

如果只是要后四位,直接slice

arr.slice(1)

隊(duì)后四位加個(gè)操作

arr.slice(1).map(x => {....})

提供個(gè)思路，你先把數(shù)組進(jìn)行一下shift或者slice等操作，得到你想要輸出的數(shù)組即可，直接map的話會(huì)出現(xiàn)undefined

var arr = ['a', 'b', 'c', 'd', 'e', 'f', 'g']
    arr.map((item, index) = >{
        if (index > 0) return item
})

//[undefined, "b", "c", "d", "e", "f", "g"]

這都還要來(lái)問(wèn)，你還寫(xiě)什么代碼？

那就用filter。

let newList = [1,2,3,4,5].filter((val, i) => i > 0).map(val => ···);

let [_,...res] = ['a','b','c','d','e'];
console.log(res);//["b", "c", "d", "e"]

var arr = ['a','b','c','d','e'];
var result = arr.filter((el, index) => {
    return index > 0;
});
console.log(result);
// ["b", "c", "d", "e"]