測(cè)資:

data = [1, 2, 3, 4]

代碼:

from itertools import accumulate

data1 = [v + (data[i-1] if i > 0 else 0) for i, v in enumerate(data)]
data2 = list(accumulate(data))

print(data1)
print(data2)

結(jié)果:

[1, 3, 5, 7]
[1, 3, 6, 10]

我回答過的問題: Python-QA

data1= data[:1] + [x+y for x,y in zip(data[1:],data[:-1])]
data1= data[:1] + [sum(data[x:x+2]) for x in range(len(data)-1)]
data2= [sum(data[:x]) for x in range(1,len(data)+1)]

data1 其實(shí)你也可以用帶 if else的列表推到而不用單獨(dú)處理第一個(gè)。
data1= [sum(data[x-1:x+1]) if x>0 else data[0] for x in range(0,len(data))]

from itertools import accumulate
data = [1, 2, 3, 4]

data1 = [x + y for x, y in enumerate(data)]
data2 = list(accumulate(data))

print(data1)
print(data2)

pre = 0
def foo(x):
    global pre
    y = x + pre
    pre = x
    return y

subtotal = 0
def bar(x):
    global subtotal
    subtotal = x + subtotal
    return subtotal

data = [1, 2, 3, 4]

data1 = list(map(foo, data))

data2 = list(map(bar, data))

print(data1, data2)