解決

      const test = [1, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]
      const func = function (arry, length) {
        let result = []
        arry.forEach((ele, index) => {
          const i = Math.floor(index / length)
          console.log(i)
          if (!result[i]) {
            result[i] = []
          }
        })
        return result
      }
      console.log(func(test, 5))

原理

就是除法運算,根據(jù)需要的長度來組合二維數(shù)組
有點類似于九九乘法表

自己把數(shù)據(jù)封裝好再循環(huán)就好啦

const test = [1, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3]
const i = Math.floor(index / length);
let result = []
result[0]= test.slice(0,i-1);
result[1]= test.slice(i-1,test.length-1);
//最后拿resul循環(huán)即可