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1.tomcat啟用gzip
2.使用cdn加速你的靜態(tài)資源

duration Number 否 指定錄音的時(shí)長(zhǎng)，單位 ms ，如果傳入了合法的 duration ，在到達(dá)指定的 duration 后會(huì)自動(dòng)停止錄音，最大值 600000（10 分鐘）,默認(rèn)值 60000（1 分鐘）

birt

公司正在用

在命令行中測(cè)試了30余次不會(huì)出現(xiàn)亂序的問(wèn)題，確定是pycharm本身的問(wèn)題。

兄弟，怎么說(shuō)呢！這個(gè)吧就像是一個(gè)規(guī)定，就像不同的公司有不同的制度，所以你寫(xiě)的代碼，在windows上可以運(yùn)行，但是不能在其它系統(tǒng)上運(yùn)行

xml分行寫(xiě)，就沒(méi)有問(wèn)題了。

sf上難得的好問(wèn)題，你貼的信息還不夠全，在發(fā)生full gc的時(shí)候，登上機(jī)器用top -H找到最忙的線(xiàn)程pid，再用jstack dump當(dāng)時(shí)的線(xiàn)程快照，把這個(gè)貼上來(lái)，還有開(kāi)啟gc.log會(huì)有更多的現(xiàn)場(chǎng)信息，看看具體是哪塊不夠觸發(fā)了fullgc。單純的看你描述的問(wèn)題來(lái)看，有點(diǎn)像某些邏輯存在內(nèi)存泄露，就算fullgc了也趕不上內(nèi)存增長(zhǎng)的速度。

C或C++程序編譯后就會(huì)失去程序中的很多信息，包括類(lèi)名、方法名、字段名等，所以想在運(yùn)行期間獲得這些內(nèi)容是很難的。這一點(diǎn)與Python等支持反射的語(yǔ)言有很大不同。

至于導(dǎo)出調(diào)試信息，只是說(shuō)在可執(zhí)行程序中加了一段數(shù)據(jù)，用來(lái)標(biāo)識(shí)可執(zhí)行文件與源代碼的一些映射，從而讓調(diào)試變得方便。但是調(diào)試信息是給調(diào)試器用的，程序自身并不能夠直接獲取這些信息，除非你自己解析二進(jìn)制格式的可執(zhí)行文件。

所以回到你的問(wèn)題上來(lái)，雖然很多語(yǔ)言都提供了反射機(jī)制，但C/C++這種相對(duì)比較“底層”的語(yǔ)言并沒(méi)有提供。

假如在webapp下面建兩個(gè)文件夾cookie1和cookie2,
cookie.setPath("/cookie1");
cookie1文件夾下面的所有頁(yè)面都能讀取cookie,cookie2下面的頁(yè)面讀取不到

四個(gè)角定各位個(gè)定位一個(gè)透明的方塊，方塊各加兩條邊

    <style>
        .item{
            height: 50px;
            width: 250px;
            background: #ccc;
            position: relative;
        }
        .item-horn{
            position: absolute;
            width: 20px;
            height: 20px;
        }
        .item-left-top{
            top: 0;
            left: 0;
            border-top: 2px solid red;
            border-left: 2px solid red;
        }
        .item-right-top{
            top: 0;
            right: 0;
            border-top: 2px solid red;
            border-right: 2px solid red;
        }
        .item-left-bottom{
            bottom: 0;
            left: 0;
            border-bottom: 2px solid red;
            border-left: 2px solid red;
        }
        .item-right-bottom{
            bottom: 0;
            right: 0;
            border-bottom: 2px solid red;
            border-right: 2px solid red;
        }
    </style>
    
    
        
    <div class="item">
        <div class="item-horn item-left-top"></div>
        <div class="item-horn item-right-top"></div>
        <div class="item-horn item-left-bottom"></div>
        <div class="item-horn item-right-bottom"></div>
    </div>
    
    
    

我將問(wèn)題中的‘開(kāi)放應(yīng)用’定義為saas平臺(tái)提供的服務(wù)吧。
例如天氣查詢(xún)，一般作為開(kāi)放應(yīng)用，對(duì)外會(huì)提供API給其他開(kāi)發(fā)者使用，一般會(huì)要求開(kāi)發(fā)者申請(qǐng)一個(gè)appkey，然后每次請(qǐng)求的時(shí)候帶上appkey（還有的會(huì)需要帶上timestamp，甚至是sign），后端核對(duì)通過(guò)后響應(yīng)請(qǐng)求，也就是將天氣信息返回給其他那位開(kāi)發(fā)者。

簡(jiǎn)單來(lái)說(shuō)是有特別的標(biāo)志位。Wiki上是這么說(shuō)的：

In IEEE 754 standard-conforming floating-point storage formats, NaNs are identified by specific, pre-defined bit patterns unique to NaNs. The sign bit does not matter. Binary format NaNs are represented with the exponential field filled with ones (like infinity values), and some non-zero number in the significand field (to make them distinct from infinity values). The original IEEE 754 standard from 1985 (IEEE 754-1985) only described binary floating-point formats, and did not specify how the signaling/quiet state was to be tagged. In practice, the most significant bit of the significand field determined whether a NaN is signaling or quiet. Two different implementations, with reversed meanings, resulted:
most processors (including those of the Intel and AMD's x86 family, the Motorola 68000 family, the AIM PowerPC family, the ARM family, the Sun SPARC family, and optionally new MIPS processors) set the signaling/quiet bit to non-zero if the NaN is quiet, and to zero if the NaN is signaling. Thus, on these processors, the bit represents an 'is_quiet' flag;
in NaNs generated by the PA-RISC and old MIPS processors, the signaling/quiet bit is zero if the NaN is quiet, and non-zero if the NaN is signaling. Thus, on these processors, the bit represents an 'is_signaling' flag.
The former choice has been preferred as it allows the implementation to quiet a signaling NaN by just setting the signaling/quiet bit to 1. The reverse is not possible with the latter choice because setting the signaling/quiet bit to 0 could yield an infinity.
The 2008 revision of the IEEE 754 standard (IEEE 754-2008) makes formal recommendations for the encoding of the signaling/quiet state.
For binary formats, the most significant bit of the significand field should be an 'is_quiet' flag. I.e. this bit is non-zero if the NaN is quiet, and zero if the NaN is signaling.
For decimal formats, whether binary or decimal encoded, a NaN is identified by having the top five bits of the combination field after the sign bit set to ones. The sixth bit of the field is the 'is_quiet' flag. The standard follows the interpretation as an 'is_signaling' flag. I.e. the signaling/quiet bit is zero if the NaN is quiet, and non-zero if the NaN is signaling. A signaling NaN is quieted by clearing this sixth bit.
For IEEE 754-2008 conformance, the meaning of the signaling/quiet bit in recent MIPS processors is now configurable via the NAN2008 field of the FCSR register. This support is optional in MIPS Release 3 and required in Release 5.[10]
The state/value of the remaining bits of the significand field are not defined by the standard. This value is called the 'payload' of the NaN. If an operation has a single NaN input and propagates it to the output, the result NaN's payload should be that of the input NaN (this is not always possible for binary formats when the signaling/quiet state is encoded by an 'is_signaling' flag, as explained above). If there are multiple NaN inputs, the result NaN's payload should be from one of the input NaNs; the standard does not specify which.

1.這么寫(xiě)肯定是會(huì)不對(duì)的，會(huì)崩潰。稍微寫(xiě)個(gè)小測(cè)試，確實(shí)會(huì)奔潰。

Book *book = [[Book alloc] init];

{    //從作用域出去后store就會(huì)釋放
    Store *store = [[Store alloc] init];
    book.delegate = store;
}
[book test];
.....
-(void)test{
    
    NSLog(@"book test");
    
    if ([self.delegate respondsToSelector:@selector(testDelegate)]) {
        [self.delegate testDelegate];
    }
}

2.為什么沒(méi)出現(xiàn)奔潰？可能是delegate很少優(yōu)先于self釋放，可能delegate因?yàn)槠渌驔](méi)釋放(單例或者引用循環(huán)等)。一般來(lái)說(shuō)被委托者應(yīng)該在更深的層級(jí)，會(huì)先釋放，比如界面A->B->C,這樣情況，肯定是C作為B的委托，C會(huì)先于B釋放。這個(gè)問(wèn)題你逐個(gè)的檢查一下為什么沒(méi)有奔潰。主要看：是否delegate釋放了還回去調(diào)用self.delegate之類(lèi)的。

c++ std庫(kù)里有個(gè)類(lèi)bitset, 是專(zhuān)門(mén)做這個(gè)事的

這里有源碼, 如果你一定要c, 可以看看這個(gè)
https://gcc.gnu.org/onlinedoc...

重點(diǎn)是left_shift和right_shift

字符串和bitset的轉(zhuǎn)換可以看這里

http://blog.csdn.net/magicyan...

即使頁(yè)面都已經(jīng)加載完了也會(huì)出現(xiàn)，只需要快速上下滾動(dòng)

樓主的問(wèn)題

1. 限制同一用戶(hù)在不同瀏覽器登陸的功能，利用session這個(gè)方案是否合理？-- 合理
2. 我理解每個(gè)瀏覽器向后端發(fā)送請(qǐng)求后，都會(huì)形成相應(yīng)的session保存起來(lái)，查詢(xún)session數(shù)據(jù)一般是怎樣實(shí)現(xiàn)的？例如，怎樣查詢(xún)包含”user“的session的”id“ -- 這個(gè)是session store的實(shí)現(xiàn)細(xì)節(jié)，不同的store不一樣，一般是存在數(shù)據(jù)庫(kù)里（mysql、mongo、redis等）。session id是可以自定義的，只要能跟用戶(hù)名關(guān)聯(lián)起來(lái)就行
3. 怎樣實(shí)現(xiàn)后端主動(dòng)向前端發(fā)起請(qǐng)求？比如用戶(hù)A未向后端發(fā)起請(qǐng)求的情況下，后端直接修改用戶(hù)A的cookie，使之過(guò)期？ -- 這里在服務(wù)端清除session即可，有官方的api store.destroy(sid, callback)。

怎么限制同個(gè)用戶(hù)不能多個(gè)地方同時(shí)登錄

實(shí)現(xiàn)思路樓主應(yīng)該是有的，只是實(shí)現(xiàn)細(xì)節(jié)不清楚：

1. 用戶(hù)登錄，存儲(chǔ)session。每個(gè)用戶(hù)的session對(duì)應(yīng)一個(gè)id，假設(shè)就是用戶(hù)名。
2. 用戶(hù)再次登錄，檢測(cè)當(dāng)前用戶(hù)是否已經(jīng)登錄 -> 檢測(cè)該用戶(hù)名，是否已經(jīng)存在session。

樓主不清除的應(yīng)該是，怎么把 用戶(hù)名、session id關(guān)聯(lián)起來(lái)，包括怎么在有用戶(hù)名的情況下，查詢(xún)到該用戶(hù)名對(duì)應(yīng)的session。

如果用express-session，可以這么實(shí)現(xiàn)。

genid選項(xiàng)：生成session id

genid返回的是session對(duì)應(yīng)的id，樓主根據(jù)實(shí)際情況進(jìn)行自定義。

app.use(session({
  genid: function (req) {
    return req.query.usrname; // 生成session的id
  }
}));

session檢測(cè)

用戶(hù)再次登錄，通過(guò)session id 去檢測(cè)session是否存在，以此判斷用戶(hù)是否已登錄。

app.use(function (req, res, next) {
  req.sessionStore.get(req.query.usrname, function (error, session) {
    // 如果session存在，表示用戶(hù)已在其他地方登錄
  });
});

因?yàn)槟阌袚Q行符 .只匹配所有非換行字符 [.\S\s]* 匹配所有

這不是css就能寫(xiě)的么

    body{
      -webkit-user-select: none;
    }
    .box {
      display: inline-block;
      border-bottom: 2px solid red;
    }
    .cont{
      width:150px;
      height: 8px;
      resize:vertical;
      overflow: hidden;
      margin-right: 150px;    
    }
    
    
    
    <div class="box">
  <div class="cont"></div>
</div>
<p>wwwwwwwwwwwwwwwwwww</p>

1 首先跟后臺(tái)確認(rèn)是否返回了你要的cookie信息，問(wèn)清楚放在哪里面返回的。
2 認(rèn)真檢查你console.log的res 里面。
https://blog.csdn.net/lohiauf...

應(yīng)該是<input type="file" accept="*.mp4">吧